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13140240453050 = 252262804809061
BaseRepresentation
bin1011111100110111001101…
…0111010100110110111010
31201112012020221122200121012
42333031303113110312322
53210242203023444200
643540313152113522
72524231256651114
oct277156327246672
951465227580535
1013140240453050
114206821196867
1215827bbb358a2
137441722c9509
14335dc35663b4
1517bc1b553a35
hexbf3735d4dba

13140240453050 has 12 divisors (see below), whose sum is σ = 24440847242766. Its totient is φ = 5256096181200.

The previous prime is 13140240453049. The next prime is 13140240453077. The reversal of 13140240453050 is 5035404204131.

It can be written as a sum of positive squares in 3 ways, for example, as 12210502888609 + 929737564441 = 3494353^2 + 964229^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13140240452998 and 13140240453016.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 131402404481 + ... + 131402404580.

Almost surely, 213140240453050 is an apocalyptic number.

13140240453050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13140240453050 is a deficient number, since it is larger than the sum of its proper divisors (11300606789716).

13140240453050 is a wasteful number, since it uses less digits than its factorization.

13140240453050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 262804809073 (or 262804809068 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 13140240453050 its reverse (5035404204131), we get a palindrome (18175644657181).

The spelling of 13140240453050 in words is "thirteen trillion, one hundred forty billion, two hundred forty million, four hundred fifty-three thousand, fifty".

Divisors: 1 2 5 10 25 50 262804809061 525609618122 1314024045305 2628048090610 6570120226525 13140240453050