Base | Representation |
---|---|
bin | 1011111100110111001101… |
… | …0111010100110110111010 |
3 | 1201112012020221122200121012 |
4 | 2333031303113110312322 |
5 | 3210242203023444200 |
6 | 43540313152113522 |
7 | 2524231256651114 |
oct | 277156327246672 |
9 | 51465227580535 |
10 | 13140240453050 |
11 | 4206821196867 |
12 | 15827bbb358a2 |
13 | 7441722c9509 |
14 | 335dc35663b4 |
15 | 17bc1b553a35 |
hex | bf3735d4dba |
13140240453050 has 12 divisors (see below), whose sum is σ = 24440847242766. Its totient is φ = 5256096181200.
The previous prime is 13140240453049. The next prime is 13140240453077. The reversal of 13140240453050 is 5035404204131.
It can be written as a sum of positive squares in 3 ways, for example, as 12210502888609 + 929737564441 = 3494353^2 + 964229^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13140240452998 and 13140240453016.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 131402404481 + ... + 131402404580.
Almost surely, 213140240453050 is an apocalyptic number.
13140240453050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13140240453050 is a deficient number, since it is larger than the sum of its proper divisors (11300606789716).
13140240453050 is a wasteful number, since it uses less digits than its factorization.
13140240453050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 262804809073 (or 262804809068 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 13140240453050 its reverse (5035404204131), we get a palindrome (18175644657181).
The spelling of 13140240453050 in words is "thirteen trillion, one hundred forty billion, two hundred forty million, four hundred fifty-three thousand, fifty".
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