Base | Representation |
---|---|
bin | 1011111100110111010000… |
… | …0000010100111100110111 |
3 | 1201112012021200212202110211 |
4 | 2333031310000110330313 |
5 | 3210242213301420320 |
6 | 43540314214330251 |
7 | 2524231450215166 |
oct | 277156400247467 |
9 | 51465250782424 |
10 | 13140251201335 |
11 | 4206827268145 |
12 | 1582803659987 |
13 | 7441745c084b |
14 | 335dc4b633dd |
15 | 17bc1c47855a |
hex | bf374014f37 |
13140251201335 has 32 divisors (see below), whose sum is σ = 16032335616000. Its totient is φ = 10337798814336.
The previous prime is 13140251201333. The next prime is 13140251201383. The reversal of 13140251201335 is 53310215204131.
It is a cyclic number.
It is not a de Polignac number, because 13140251201335 - 21 = 13140251201333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13140251201297 and 13140251201306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13140251201333) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 65548986 + ... + 65749144.
It is an arithmetic number, because the mean of its divisors is an integer number (501010488000).
Almost surely, 213140251201335 is an apocalyptic number.
13140251201335 is a deficient number, since it is larger than the sum of its proper divisors (2892084414665).
13140251201335 is a wasteful number, since it uses less digits than its factorization.
13140251201335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 201175.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 13140251201335 its reverse (53310215204131), we get a palindrome (66450466405466).
The spelling of 13140251201335 in words is "thirteen trillion, one hundred forty billion, two hundred fifty-one million, two hundred one thousand, three hundred thirty-five".
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