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13140252121207 is a prime number
BaseRepresentation
bin1011111100110111010000…
…0011110101100001110111
31201112012021202121111022011
42333031310003311201313
53210242214020334312
643540314250145051
72524231461066061
oct277156403654167
951465252544264
1013140252121207
114206827836272
121582803a22187
13744174853453
14335dc4d22731
1517bc1c5aada7
hexbf3740f5877

13140252121207 has 2 divisors, whose sum is σ = 13140252121208. Its totient is φ = 13140252121206.

The previous prime is 13140252121181. The next prime is 13140252121267. The reversal of 13140252121207 is 70212125204131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13140252121207 - 27 = 13140252121079 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13140252121267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570126060603 + 6570126060604.

It is an arithmetic number, because the mean of its divisors is an integer number (6570126060604).

Almost surely, 213140252121207 is an apocalyptic number.

13140252121207 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140252121207 is an equidigital number, since it uses as much as digits as its factorization.

13140252121207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 31.

Adding to 13140252121207 its reverse (70212125204131), we get a palindrome (83352377325338).

The spelling of 13140252121207 in words is "thirteen trillion, one hundred forty billion, two hundred fifty-two million, one hundred twenty-one thousand, two hundred seven".