131403021333442 has 4 divisors (see below), whose sum is σ = 197104532000166. Its totient is φ = 65701510666720.

The previous prime is 131403021333439. The next prime is 131403021333457. The reversal of 131403021333442 is 244333120304131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 84350980749841 + 47052040583601 = 9184279^2 + 6859449^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131403021333398 and 131403021333407.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32850755333359 + ... + 32850755333362.

Almost surely, 2^{131403021333442} is an apocalyptic number.

131403021333442 is a deficient number, since it is larger than the sum of its proper divisors (65701510666724).

131403021333442 is an equidigital number, since it uses as much as digits as its factorization.

131403021333442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65701510666723.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 131403021333442 its reverse (244333120304131), we get a palindrome (375736141637573).

The spelling of 131403021333442 in words is "one hundred thirty-one trillion, four hundred three billion, twenty-one million, three hundred thirty-three thousand, four hundred forty-two".