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131403032241014 = 265701516120507
BaseRepresentation
bin11101111000001010100111…
…000011110010001101110110
3122020021000012020200212221102
4131320022213003302031312
5114210401402223203024
61143245415240050102
736451361431035362
oct3570124703621566
9566230166625842
10131403032241014
1138961793037026
12128a2955763932
1358423394515c1
142463d253a42a2
15102d163a1a1ae
hex7782a70f2376

131403032241014 has 4 divisors (see below), whose sum is σ = 197104548361524. Its totient is φ = 65701516120506.

The previous prime is 131403032240981. The next prime is 131403032241017. The reversal of 131403032241014 is 410142230304131.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131403032241017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32850758060252 + ... + 32850758060255.

It is an arithmetic number, because the mean of its divisors is an integer number (49276137090381).

Almost surely, 2131403032241014 is an apocalyptic number.

131403032241014 is a deficient number, since it is larger than the sum of its proper divisors (65701516120510).

131403032241014 is an equidigital number, since it uses as much as digits as its factorization.

131403032241014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65701516120509.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 131403032241014 its reverse (410142230304131), we get a palindrome (541545262545145).

The spelling of 131403032241014 in words is "one hundred thirty-one trillion, four hundred three billion, thirty-two million, two hundred forty-one thousand, fourteen".

Divisors: 1 2 65701516120507 131403032241014