Base | Representation |
---|---|
bin | 11101111000001010110111… |
… | …000010011011100000010011 |
3 | 122020021000212221010202221212 |
4 | 131320022313002123200103 |
5 | 114210402424340240144 |
6 | 1143245502014010335 |
7 | 36451401164502506 |
oct | 3570126702334023 |
9 | 566230787122855 |
10 | 131403300321299 |
11 | 38961910399786 |
12 | 128a2a0b4a69ab |
13 | 584237cb546a6 |
14 | 2463d4cc2913d |
15 | 102d17c32149e |
hex | 7782b709b813 |
131403300321299 has 2 divisors, whose sum is σ = 131403300321300. Its totient is φ = 131403300321298.
The previous prime is 131403300321287. The next prime is 131403300321331. The reversal of 131403300321299 is 992123003304131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131403300321299 - 224 = 131403283544083 is a prime.
It is not a weakly prime, because it can be changed into another prime (131403300321229) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701650160649 + 65701650160650.
It is an arithmetic number, because the mean of its divisors is an integer number (65701650160650).
Almost surely, 2131403300321299 is an apocalyptic number.
131403300321299 is a deficient number, since it is larger than the sum of its proper divisors (1).
131403300321299 is an equidigital number, since it uses as much as digits as its factorization.
131403300321299 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 104976, while the sum is 41.
The spelling of 131403300321299 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred million, three hundred twenty-one thousand, two hundred ninety-nine".
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