131403311222433 has 8 divisors (see below), whose sum is σ = 175206025333728. Its totient is φ = 87601402296384.

The previous prime is 131403311222429. The next prime is 131403311222501. The reversal of 131403311222433 is 334222113304131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 131403311222433 - 2² = 131403311222429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131403311222394 and 131403311222403.

It is not an unprimeable number, because it can be changed into a prime (131403311221433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 200915416 + ... + 201568377.

It is an arithmetic number, because the mean of its divisors is an integer number (21900753166716).

Almost surely, 2^{131403311222433} is an apocalyptic number.

It is an amenable number.

131403311222433 is a deficient number, since it is larger than the sum of its proper divisors (43802714111295).

131403311222433 is a wasteful number, since it uses less digits than its factorization.

131403311222433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 402592623.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 131403311222433 its reverse (334222113304131), we get a palindrome (465625424526564).

The spelling of 131403311222433 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred eleven million, two hundred twenty-two thousand, four hundred thirty-three".