131403311243933 has 2 divisors, whose sum is σ = 131403311243934. Its totient is φ = 131403311243932.

The previous prime is 131403311243899. The next prime is 131403311243951. The reversal of 131403311243933 is 339342113304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119951604826564 + 11451706417369 = 10952242^2 + 3384037^2 .

It is a cyclic number.

It is not a de Polignac number, because 131403311243933 - 2¹⁰ = 131403311242909 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131403311243033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701655621966 + 65701655621967.

It is an arithmetic number, because the mean of its divisors is an integer number (65701655621967).

Almost surely, 2^{131403311243933} is an apocalyptic number.

It is an amenable number.

131403311243933 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403311243933 is an equidigital number, since it uses as much as digits as its factorization.

131403311243933 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 209952, while the sum is 41.

The spelling of 131403311243933 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred eleven million, two hundred forty-three thousand, nine hundred thirty-three".