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131403311244043 is a prime number
BaseRepresentation
bin11101111000001010110111…
…101100000110001100001011
3122020021000220200200201010221
4131320022313230012030023
5114210402440134302133
61143245503044050511
736451401356364316
oct3570126754061413
9566230820621127
10131403311244043
113896191657a143
12128a2a13093a37
1358423821aa257
142463d5046d97d
15102d17d27ca2d
hex7782b7b0630b

131403311244043 has 2 divisors, whose sum is σ = 131403311244044. Its totient is φ = 131403311244042.

The previous prime is 131403311244017. The next prime is 131403311244061. The reversal of 131403311244043 is 340442113304131.

It is a strong prime.

It is an emirp because it is prime and its reverse (340442113304131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131403311244043 - 229 = 131402774373131 is a prime.

It is not a weakly prime, because it can be changed into another prime (131403311244143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701655622021 + 65701655622022.

It is an arithmetic number, because the mean of its divisors is an integer number (65701655622022).

Almost surely, 2131403311244043 is an apocalyptic number.

131403311244043 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403311244043 is an equidigital number, since it uses as much as digits as its factorization.

131403311244043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 131403311244043 its reverse (340442113304131), we get a palindrome (471845424548174).

The spelling of 131403311244043 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred eleven million, two hundred forty-four thousand, forty-three".