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131403311244143 is a prime number
BaseRepresentation
bin11101111000001010110111…
…101100000110001101101111
3122020021000220200200201021122
4131320022313230012031233
5114210402440134303033
61143245503044051155
736451401356364521
oct3570126754061557
9566230820621248
10131403311244143
113896191657a224
12128a2a13093abb
1358423821aa303
142463d5046da11
15102d17d27ca98
hex7782b7b0636f

131403311244143 has 2 divisors, whose sum is σ = 131403311244144. Its totient is φ = 131403311244142.

The previous prime is 131403311244137. The next prime is 131403311244193. The reversal of 131403311244143 is 341442113304131.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131403311244143 - 234 = 131386131374959 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131403311244193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701655622071 + 65701655622072.

It is an arithmetic number, because the mean of its divisors is an integer number (65701655622072).

Almost surely, 2131403311244143 is an apocalyptic number.

131403311244143 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403311244143 is an equidigital number, since it uses as much as digits as its factorization.

131403311244143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 35.

Adding to 131403311244143 its reverse (341442113304131), we get a palindrome (472845424548274).

The spelling of 131403311244143 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred eleven million, two hundred forty-four thousand, one hundred forty-three".