Base | Representation |
---|---|
bin | 11101111000001010110111… |
… | …101100000110001101101111 |
3 | 122020021000220200200201021122 |
4 | 131320022313230012031233 |
5 | 114210402440134303033 |
6 | 1143245503044051155 |
7 | 36451401356364521 |
oct | 3570126754061557 |
9 | 566230820621248 |
10 | 131403311244143 |
11 | 3896191657a224 |
12 | 128a2a13093abb |
13 | 58423821aa303 |
14 | 2463d5046da11 |
15 | 102d17d27ca98 |
hex | 7782b7b0636f |
131403311244143 has 2 divisors, whose sum is σ = 131403311244144. Its totient is φ = 131403311244142.
The previous prime is 131403311244137. The next prime is 131403311244193. The reversal of 131403311244143 is 341442113304131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131403311244143 - 234 = 131386131374959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131403311244193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701655622071 + 65701655622072.
It is an arithmetic number, because the mean of its divisors is an integer number (65701655622072).
Almost surely, 2131403311244143 is an apocalyptic number.
131403311244143 is a deficient number, since it is larger than the sum of its proper divisors (1).
131403311244143 is an equidigital number, since it uses as much as digits as its factorization.
131403311244143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 35.
Adding to 131403311244143 its reverse (341442113304131), we get a palindrome (472845424548274).
The spelling of 131403311244143 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred eleven million, two hundred forty-four thousand, one hundred forty-three".
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