Base | Representation |
---|---|
bin | 1011111100110111100011… |
… | …0001010001100001111010 |
3 | 1201112012111021022010102010 |
4 | 2333031320301101201322 |
5 | 3210242344233004432 |
6 | 43540330151550350 |
7 | 2524233440541144 |
oct | 277157061214172 |
9 | 51465437263363 |
10 | 13140331141242 |
11 | 42068683a8188 |
12 | 158282638b3b6 |
13 | 74418802c776 |
14 | 335dd1611c94 |
15 | 17bc244b93cc |
hex | bf378c5187a |
13140331141242 has 8 divisors (see below), whose sum is σ = 26280662282496. Its totient is φ = 4380110380412.
The previous prime is 13140331141237. The next prime is 13140331141243. The reversal of 13140331141242 is 24214113304131.
It is a sphenic number, since it is the product of 3 distinct primes.
13140331141242 is an admirable number.
It is not an unprimeable number, because it can be changed into a prime (13140331141243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1095027595098 + ... + 1095027595109.
It is an arithmetic number, because the mean of its divisors is an integer number (3285082785312).
Almost surely, 213140331141242 is an apocalyptic number.
13140331141242 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13140331141242 is a wasteful number, since it uses less digits than its factorization.
13140331141242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2190055190212.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 13140331141242 its reverse (24214113304131), we get a palindrome (37354444445373).
The spelling of 13140331141242 in words is "thirteen trillion, one hundred forty billion, three hundred thirty-one million, one hundred forty-one thousand, two hundred forty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •