Base | Representation |
---|---|
bin | 1011111100110111100011… |
… | …0010011110001101000110 |
3 | 1201112012111021220002012222 |
4 | 2333031320302132031012 |
5 | 3210242344323032202 |
6 | 43540330202412342 |
7 | 2524233443316602 |
oct | 277157062361506 |
9 | 51465437802188 |
10 | 13140331455302 |
11 | 42068685a2137 |
12 | 15828265010b2 |
13 | 74418810c6bc |
14 | 335dd1694502 |
15 | 17bc2452c4a2 |
hex | bf378c9e346 |
13140331455302 has 4 divisors (see below), whose sum is σ = 19710497182956. Its totient is φ = 6570165727650.
The previous prime is 13140331455247. The next prime is 13140331455379. The reversal of 13140331455302 is 20355413304131.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×131403314553022 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3285082863824 + ... + 3285082863827.
It is an arithmetic number, because the mean of its divisors is an integer number (4927624295739).
Almost surely, 213140331455302 is an apocalyptic number.
13140331455302 is a deficient number, since it is larger than the sum of its proper divisors (6570165727654).
13140331455302 is an equidigital number, since it uses as much as digits as its factorization.
13140331455302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6570165727653.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 13140331455302 its reverse (20355413304131), we get a palindrome (33495744759433).
The spelling of 13140331455302 in words is "thirteen trillion, one hundred forty billion, three hundred thirty-one million, four hundred fifty-five thousand, three hundred two".
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