131403322410131 has 4 divisors (see below), whose sum is σ = 133254073430064. Its totient is φ = 129552571390200.

The previous prime is 131403322410121. The next prime is 131403322410161. The reversal of 131403322410131 is 131014223304131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131403322410131 - 2¹⁸ = 131403322147987 is a prime.

It is a super-2 number, since 2×131403322410131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131403322410094 and 131403322410103.

It is not an unprimeable number, because it can be changed into a prime (131403322410121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 925375509860 + ... + 925375510001.

It is an arithmetic number, because the mean of its divisors is an integer number (33313518357516).

Almost surely, 2^{131403322410131} is an apocalyptic number.

131403322410131 is a deficient number, since it is larger than the sum of its proper divisors (1850751019933).

131403322410131 is an equidigital number, since it uses as much as digits as its factorization.

131403322410131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1850751019932.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 131403322410131 its reverse (131014223304131), we get a palindrome (262417545714262).

The spelling of 131403322410131 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred twenty-two million, four hundred ten thousand, one hundred thirty-one".