Base | Representation |
---|---|
bin | 10011000111110010011… |
… | …110111101000101100111 |
3 | 11122121202020100012102111 |
4 | 103013302132331011213 |
5 | 133012120001213322 |
6 | 2443354124221451 |
7 | 163635653063101 |
oct | 23076236750547 |
9 | 4577666305374 |
10 | 1314033226087 |
11 | 4673075546aa |
12 | 19280309a887 |
13 | 96bb356a80a |
14 | 47857230571 |
15 | 242aae1d177 |
hex | 131f27bd167 |
1314033226087 has 2 divisors, whose sum is σ = 1314033226088. Its totient is φ = 1314033226086.
The previous prime is 1314033226081. The next prime is 1314033226171. The reversal of 1314033226087 is 7806223304131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1314033226087 - 211 = 1314033224039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314033226081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657016613043 + 657016613044.
It is an arithmetic number, because the mean of its divisors is an integer number (657016613044).
Almost surely, 21314033226087 is an apocalyptic number.
1314033226087 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314033226087 is an equidigital number, since it uses as much as digits as its factorization.
1314033226087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 40.
The spelling of 1314033226087 in words is "one trillion, three hundred fourteen billion, thirty-three million, two hundred twenty-six thousand, eighty-seven".
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