Base | Representation |
---|---|
bin | 10011000111110010011… |
… | …110111110010111101101 |
3 | 11122121202020100110122002 |
4 | 103013302132332113231 |
5 | 133012120001400331 |
6 | 2443354124302045 |
7 | 163635653114315 |
oct | 23076236762755 |
9 | 4577666313562 |
10 | 1314033231341 |
11 | 467307558646 |
12 | 1928030a1925 |
13 | 96bb357001c |
14 | 47857232445 |
15 | 242aae1e9cb |
hex | 131f27be5ed |
1314033231341 has 2 divisors, whose sum is σ = 1314033231342. Its totient is φ = 1314033231340.
The previous prime is 1314033231331. The next prime is 1314033231349. The reversal of 1314033231341 is 1431323304131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1017929655625 + 296103575716 = 1008925^2 + 544154^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314033231341 - 238 = 1039155324397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314033231349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657016615670 + 657016615671.
It is an arithmetic number, because the mean of its divisors is an integer number (657016615671).
Almost surely, 21314033231341 is an apocalyptic number.
It is an amenable number.
1314033231341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314033231341 is an equidigital number, since it uses as much as digits as its factorization.
1314033231341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 1314033231341 its reverse (1431323304131), we get a palindrome (2745356535472).
The spelling of 1314033231341 in words is "one trillion, three hundred fourteen billion, thirty-three million, two hundred thirty-one thousand, three hundred forty-one".
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