131403352511239 has 2 divisors, whose sum is σ = 131403352511240. Its totient is φ = 131403352511238.

The previous prime is 131403352511173. The next prime is 131403352511257. The reversal of 131403352511239 is 932115253304131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131403352511239 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131403352511195 and 131403352511204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131403352511839) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701676255619 + 65701676255620.

It is an arithmetic number, because the mean of its divisors is an integer number (65701676255620).

Almost surely, 2^{131403352511239} is an apocalyptic number.

131403352511239 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403352511239 is an equidigital number, since it uses as much as digits as its factorization.

131403352511239 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 291600, while the sum is 43.

The spelling of 131403352511239 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred fifty-two million, five hundred eleven thousand, two hundred thirty-nine".