131403400403534 has 32 divisors (see below), whose sum is σ = 229102588823040. Its totient is φ = 55356018856992.

The previous prime is 131403400403417. The next prime is 131403400403557. The reversal of 131403400403534 is 435304004304131.

It is a super-2 number, since 2×131403400403534² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131403400403494 and 131403400403503.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1271567 + ... + 16261109.

It is an arithmetic number, because the mean of its divisors is an integer number (7159455900720).

Almost surely, 2^{131403400403534} is an apocalyptic number.

131403400403534 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

131403400403534 is a deficient number, since it is larger than the sum of its proper divisors (97699188419506).

131403400403534 is a wasteful number, since it uses less digits than its factorization.

131403400403534 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15000224.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 131403400403534 its reverse (435304004304131), we get a palindrome (566707404707665).

The spelling of 131403400403534 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred million, four hundred three thousand, five hundred thirty-four".