131403404332211 has 4 divisors (see below), whose sum is σ = 143349168362424. Its totient is φ = 119457640302000.

The previous prime is 131403404332183. The next prime is 131403404332219. The reversal of 131403404332211 is 112233404304131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 131403404332211 - 2¹⁸ = 131403404070067 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131403404332219) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5972882015090 + ... + 5972882015111.

It is an arithmetic number, because the mean of its divisors is an integer number (35837292090606).

Almost surely, 2^{131403404332211} is an apocalyptic number.

131403404332211 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

131403404332211 is a deficient number, since it is larger than the sum of its proper divisors (11945764030213).

131403404332211 is a wasteful number, since it uses less digits than its factorization.

131403404332211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11945764030212.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 131403404332211 its reverse (112233404304131), we get a palindrome (243636808636342).

The spelling of 131403404332211 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred four million, three hundred thirty-two thousand, two hundred eleven".