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131403434321443 is a prime number
BaseRepresentation
bin11101111000001010111111…
…000001100110011000100011
3122020021001020021021200121011
4131320022333001212120203
5114210403213141241233
61143245523202041351
736451404412463464
oct3570127701463043
9566231207250534
10131403434321443
1138961979aa2aa9
12128a2a48349257
1358423a1840b0b
142463d6294ad6b
15102d188e900cd
hex7782bf066623

131403434321443 has 2 divisors, whose sum is σ = 131403434321444. Its totient is φ = 131403434321442.

The previous prime is 131403434321437. The next prime is 131403434321483. The reversal of 131403434321443 is 344123434304131.

It is an a-pointer prime, because the next prime (131403434321483) can be obtained adding 131403434321443 to its sum of digits (40).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131403434321443 - 233 = 131394844386851 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131403434321396 and 131403434321405.

It is not a weakly prime, because it can be changed into another prime (131403434321483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701717160721 + 65701717160722.

It is an arithmetic number, because the mean of its divisors is an integer number (65701717160722).

Almost surely, 2131403434321443 is an apocalyptic number.

131403434321443 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403434321443 is an equidigital number, since it uses as much as digits as its factorization.

131403434321443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 497664, while the sum is 40.

Adding to 131403434321443 its reverse (344123434304131), we get a palindrome (475526868625574).

The spelling of 131403434321443 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred thirty-four million, three hundred twenty-one thousand, four hundred forty-three".