1314034351241 has 2 divisors, whose sum is σ = 1314034351242. Its totient is φ = 1314034351240.

The previous prime is 1314034351211. The next prime is 1314034351271. The reversal of 1314034351241 is 1421534304131.

It is a balanced prime because it is at equal distance from previous prime (1314034351211) and next prime (1314034351271).

It can be written as a sum of positive squares in only one way, i.e., 1270194366841 + 43839984400 = 1127029^2 + 209380^2 .

It is an emirp because it is prime and its reverse (1421534304131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1314034351241 - 2²⁶ = 1313967242377 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1314034351198 and 1314034351207.

It is not a weakly prime, because it can be changed into another prime (1314034351211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657017175620 + 657017175621.

It is an arithmetic number, because the mean of its divisors is an integer number (657017175621).

Almost surely, 2^{1314034351241} is an apocalyptic number.

It is an amenable number.

1314034351241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314034351241 is an equidigital number, since it uses as much as digits as its factorization.

1314034351241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 1314034351241 its reverse (1421534304131), we get a palindrome (2735568655372).

The spelling of 1314034351241 in words is "one trillion, three hundred fourteen billion, thirty-four million, three hundred fifty-one thousand, two hundred forty-one".