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13140345203413 is a prime number
BaseRepresentation
bin1011111100110111100110…
…0110111010101011010101
31201112012112020202120002021
42333031321212322223111
53210242411333002123
643540331413213141
72524234001216551
oct277157146725325
951465466676067
1013140345203413
11420687533230a
12158282b0311b1
1374418ac1428c
14335dd3432861
1517bc25845c5d
hexbf3799baad5

13140345203413 has 2 divisors, whose sum is σ = 13140345203414. Its totient is φ = 13140345203412.

The previous prime is 13140345203383. The next prime is 13140345203423. The reversal of 13140345203413 is 31430254304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12492421629444 + 647923573969 = 3534462^2 + 804937^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13140345203413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13140345203423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570172601706 + 6570172601707.

It is an arithmetic number, because the mean of its divisors is an integer number (6570172601707).

Almost surely, 213140345203413 is an apocalyptic number.

It is an amenable number.

13140345203413 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140345203413 is an equidigital number, since it uses as much as digits as its factorization.

13140345203413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 13140345203413 its reverse (31430254304131), we get a palindrome (44570599507544).

The spelling of 13140345203413 in words is "thirteen trillion, one hundred forty billion, three hundred forty-five million, two hundred three thousand, four hundred thirteen".