13140352445051 has 4 divisors (see below), whose sum is σ = 14151148786992. Its totient is φ = 12129556103112.

The previous prime is 13140352444997. The next prime is 13140352445117. The reversal of 13140352445051 is 15054425304131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13140352445051 - 2³⁰ = 13139278703227 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13140352444996 and 13140352445014.

It is not an unprimeable number, because it can be changed into a prime (13140352445651) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 505398170951 + ... + 505398170976.

It is an arithmetic number, because the mean of its divisors is an integer number (3537787196748).

Almost surely, 2^{13140352445051} is an apocalyptic number.

13140352445051 is a deficient number, since it is larger than the sum of its proper divisors (1010796341941).

13140352445051 is a wasteful number, since it uses less digits than its factorization.

13140352445051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1010796341940.

The product of its (nonzero) digits is 144000, while the sum is 38.

Adding to 13140352445051 its reverse (15054425304131), we get a palindrome (28194777749182).

The spelling of 13140352445051 in words is "thirteen trillion, one hundred forty billion, three hundred fifty-two million, four hundred forty-five thousand, fifty-one".