13140354433 has 8 divisors (see below), whose sum is σ = 13177675368. Its totient is φ = 13103086464.

The previous prime is 13140354407. The next prime is 13140354439. The reversal of 13140354433 is 33445304131.

13140354433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 4593721729 + 8546632704 = 67777^2 + 92448^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13140354433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13140354395 and 13140354404.

It is not an unprimeable number, because it can be changed into a prime (13140354439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 512835 + ... + 537847.

It is an arithmetic number, because the mean of its divisors is an integer number (1647209421).

Almost surely, 2^13140354433 is an apocalyptic number.

It is an amenable number.

13140354433 is a deficient number, since it is larger than the sum of its proper divisors (37320935).

13140354433 is an equidigital number, since it uses as much as digits as its factorization.

13140354433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26483.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 13140354433 its reverse (33445304131), we get a palindrome (46585658564).

The spelling of 13140354433 in words is "thirteen billion, one hundred forty million, three hundred fifty-four thousand, four hundred thirty-three".