Base | Representation |
---|---|
bin | 11101111000001011100010… |
… | …001011110110111001101111 |
3 | 122020021002202101021021211102 |
4 | 131320023202023312321233 |
5 | 114210410420144304403 |
6 | 1143250101513313315 |
7 | 36451425134462315 |
oct | 3570134213667157 |
9 | 566232671237742 |
10 | 131404024213103 |
11 | 38962151a77374 |
12 | 128a2b91a0583b |
13 | 5842466b0a735 |
14 | 2463dbb0220b5 |
15 | 102d1c0b62b88 |
hex | 7782e22f6e6f |
131404024213103 has 4 divisors (see below), whose sum is σ = 131594189227128. Its totient is φ = 131213859199080.
The previous prime is 131404024213037. The next prime is 131404024213151. The reversal of 131404024213103 is 301312420404131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131404024213103 - 216 = 131404024147567 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131404024213183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95082505976 + ... + 95082507357.
It is an arithmetic number, because the mean of its divisors is an integer number (32898547306782).
Almost surely, 2131404024213103 is an apocalyptic number.
131404024213103 is a deficient number, since it is larger than the sum of its proper divisors (190165014025).
131404024213103 is an equidigital number, since it uses as much as digits as its factorization.
131404024213103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 190165014024.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 131404024213103 its reverse (301312420404131), we get a palindrome (432716444617234).
The spelling of 131404024213103 in words is "one hundred thirty-one trillion, four hundred four billion, twenty-four million, two hundred thirteen thousand, one hundred three".
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