131404030130042 has 4 divisors (see below), whose sum is σ = 197106045195066. Its totient is φ = 65702015065020.

The previous prime is 131404030130017. The next prime is 131404030130089. The reversal of 131404030130042 is 240031030404131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 130760391372601 + 643638757441 = 11435051^2 + 802271^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131404030129993 and 131404030130020.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32851007532509 + ... + 32851007532512.

Almost surely, 2^{131404030130042} is an apocalyptic number.

131404030130042 is a deficient number, since it is larger than the sum of its proper divisors (65702015065024).

131404030130042 is an equidigital number, since it uses as much as digits as its factorization.

131404030130042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65702015065023.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 131404030130042 its reverse (240031030404131), we get a palindrome (371435060534173).

The spelling of 131404030130042 in words is "one hundred thirty-one trillion, four hundred four billion, thirty million, one hundred thirty thousand, forty-two".