Base | Representation |
---|---|
bin | 11101111000001011100010… |
… | …100010011110111101010101 |
3 | 122020021002202210102121221220 |
4 | 131320023202202132331111 |
5 | 114210410423204104331 |
6 | 1143250102244400553 |
7 | 36451425236054463 |
oct | 3570134242367525 |
9 | 566232683377856 |
10 | 131404030144341 |
11 | 38962155358619 |
12 | 128a2b939a6159 |
13 | 5842468106346 |
14 | 2463dbbb27833 |
15 | 102d1c1435296 |
hex | 7782e289ef55 |
131404030144341 has 16 divisors (see below), whose sum is σ = 181965912652800. Its totient is φ = 84285599808368.
The previous prime is 131404030144319. The next prime is 131404030144351. The reversal of 131404030144341 is 143441030404131.
It is a cyclic number.
It is not a de Polignac number, because 131404030144341 - 211 = 131404030142293 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131404030144351) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7897817751 + ... + 7897834388.
It is an arithmetic number, because the mean of its divisors is an integer number (11372869540800).
Almost surely, 2131404030144341 is an apocalyptic number.
It is an amenable number.
131404030144341 is a deficient number, since it is larger than the sum of its proper divisors (50561882508459).
131404030144341 is a wasteful number, since it uses less digits than its factorization.
131404030144341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15795652248.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 131404030144341 its reverse (143441030404131), we get a palindrome (274845060548472).
The spelling of 131404030144341 in words is "one hundred thirty-one trillion, four hundred four billion, thirty million, one hundred forty-four thousand, three hundred forty-one".
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