131404030144342 has 8 divisors (see below), whose sum is σ = 197107598310336. Its totient is φ = 65701497374232.

The previous prime is 131404030144319. The next prime is 131404030144351. The reversal of 131404030144342 is 243441030404131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×131404030144342³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 131404030144298 and 131404030144307.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 258531613 + ... + 259039384.

It is an arithmetic number, because the mean of its divisors is an integer number (24638449788792).

Almost surely, 2^{131404030144342} is an apocalyptic number.

131404030144342 is a deficient number, since it is larger than the sum of its proper divisors (65703568165994).

131404030144342 is a wasteful number, since it uses less digits than its factorization.

131404030144342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 517697942.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 131404030144342 its reverse (243441030404131), we get a palindrome (374845060548473).

The spelling of 131404030144342 in words is "one hundred thirty-one trillion, four hundred four billion, thirty million, one hundred forty-four thousand, three hundred forty-two".