13140411051040 has 192 divisors, whose sum is σ = 38214582610176. Its totient is φ = 4158036652032.

The previous prime is 13140411051037. The next prime is 13140411051041. The reversal of 13140411051040 is 4015011404131.

13140411051040 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 13140411050996 and 13140411051014.

It is not an unprimeable number, because it can be changed into a prime (13140411051041) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 91991514 + ... + 92134246.

It is an arithmetic number, because the mean of its divisors is an integer number (199034284428).

Almost surely, 2^{13140411051040} is an apocalyptic number.

13140411051040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13140411051040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19107291305088).

13140411051040 is an abundant number, since it is smaller than the sum of its proper divisors (25074171559136).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13140411051040 is a wasteful number, since it uses less digits than its factorization.

13140411051040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 149091 (or 149083 counting only the distinct ones).

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 13140411051040 its reverse (4015011404131), we get a palindrome (17155422455171).

The spelling of 13140411051040 in words is "thirteen trillion, one hundred forty billion, four hundred eleven million, fifty-one thousand, forty".