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131404120234 = 285776665181
BaseRepresentation
bin111101001100001001…
…0111100000010101010
3110120011210000221110221
41322120102330002222
54123103423321414
6140211034200254
712331213410232
oct1723022740252
9416153027427
10131404120234
1150801222482
1221572b8308a
13c511a667ca
146507b70cc2
15364126e224
hex1e984bc0aa

131404120234 has 8 divisors (see below), whose sum is σ = 197336178468. Its totient is φ = 65625394080.

The previous prime is 131404120223. The next prime is 131404120249. The reversal of 131404120234 is 432021404131.

It can be written as a sum of positive squares in 2 ways, for example, as 90723247209 + 40680873025 = 301203^2 + 201695^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 131404120199 and 131404120208.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38330877 + ... + 38334304.

Almost surely, 2131404120234 is an apocalyptic number.

131404120234 is a deficient number, since it is larger than the sum of its proper divisors (65932058234).

131404120234 is an equidigital number, since it uses as much as digits as its factorization.

131404120234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76666040.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 131404120234 its reverse (432021404131), we get a palindrome (563425524365).

The spelling of 131404120234 in words is "one hundred thirty-one billion, four hundred four million, one hundred twenty thousand, two hundred thirty-four".

Divisors: 1 2 857 1714 76665181 153330362 65702060117 131404120234