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1314042422323 = 5023261605101
BaseRepresentation
bin10011000111110011000…
…010000010010000110011
311122121202212122102021211
4103013303002002100303
5133012124330003243
62443355053300551
7163636124204221
oct23076302022063
94577685572254
101314042422323
114673117659a4
12192806194757
1396bb543a587
1447858545b11
15242abb37d9d
hex131f3082433

1314042422323 has 4 divisors (see below), whose sum is σ = 1314304032448. Its totient is φ = 1313780812200.

The previous prime is 1314042422299. The next prime is 1314042422351. The reversal of 1314042422323 is 3232242404131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1314042422323 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1314042422383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130797528 + ... + 130807573.

It is an arithmetic number, because the mean of its divisors is an integer number (328576008112).

Almost surely, 21314042422323 is an apocalyptic number.

1314042422323 is a deficient number, since it is larger than the sum of its proper divisors (261610125).

1314042422323 is an equidigital number, since it uses as much as digits as its factorization.

1314042422323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 261610124.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 1314042422323 its reverse (3232242404131), we get a palindrome (4546284826454).

The spelling of 1314042422323 in words is "one trillion, three hundred fourteen billion, forty-two million, four hundred twenty-two thousand, three hundred twenty-three".

Divisors: 1 5023 261605101 1314042422323