Base | Representation |
---|---|
bin | 11101111000001011110100… |
… | …011011111010010001011111 |
3 | 122020021010112201102202112002 |
4 | 131320023310123322101133 |
5 | 114210412032041123403 |
6 | 1143250152132232515 |
7 | 36451435543225001 |
oct | 3570136433722137 |
9 | 566233481382462 |
10 | 131404330411103 |
11 | 389622998a4472 |
12 | 128a305846b73b |
13 | 58424b5398699 |
14 | 246400996a371 |
15 | 102d1dc998188 |
hex | 7782f46fa45f |
131404330411103 has 2 divisors, whose sum is σ = 131404330411104. Its totient is φ = 131404330411102.
The previous prime is 131404330411097. The next prime is 131404330411129. The reversal of 131404330411103 is 301114033404131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131404330411103 - 216 = 131404330345567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131404330411603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65702165205551 + 65702165205552.
It is an arithmetic number, because the mean of its divisors is an integer number (65702165205552).
Almost surely, 2131404330411103 is an apocalyptic number.
131404330411103 is a deficient number, since it is larger than the sum of its proper divisors (1).
131404330411103 is an equidigital number, since it uses as much as digits as its factorization.
131404330411103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 131404330411103 its reverse (301114033404131), we get a palindrome (432518363815234).
The spelling of 131404330411103 in words is "one hundred thirty-one trillion, four hundred four billion, three hundred thirty million, four hundred eleven thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •