Base | Representation |
---|---|
bin | 10011000111110011000… |
… | …101011011011111110010 |
3 | 11122121202221022121212001 |
4 | 103013303011123133302 |
5 | 133012130041441424 |
6 | 2443355124324214 |
7 | 163636134601321 |
oct | 23076305333762 |
9 | 4577687277761 |
10 | 1314043312114 |
11 | 467312213465 |
12 | 19280654366a |
13 | 96bb568c590 |
14 | 478586d80b8 |
15 | 242abc61844 |
hex | 131f315b7f2 |
1314043312114 has 16 divisors (see below), whose sum is σ = 2214976018752. Its totient is φ = 580112766288.
The previous prime is 1314043312103. The next prime is 1314043312129. The reversal of 1314043312114 is 4112133404131.
It is a super-2 number, since 2×13140433121142 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1098697824 + ... + 1098699019.
It is an arithmetic number, because the mean of its divisors is an integer number (138436001172).
Almost surely, 21314043312114 is an apocalyptic number.
1314043312114 is a deficient number, since it is larger than the sum of its proper divisors (900932706638).
1314043312114 is a wasteful number, since it uses less digits than its factorization.
1314043312114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2197396881.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 1314043312114 its reverse (4112133404131), we get a palindrome (5426176716245).
The spelling of 1314043312114 in words is "one trillion, three hundred fourteen billion, forty-three million, three hundred twelve thousand, one hundred fourteen".
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