Base | Representation |
---|---|
bin | 11101111000001011110101… |
… | …010000001010110010100011 |
3 | 122020021010120200012202012122 |
4 | 131320023311100022302203 |
5 | 114210412044043011433 |
6 | 1143250153342014455 |
7 | 36451436100532121 |
oct | 3570136520126243 |
9 | 566233520182178 |
10 | 131404344110243 |
11 | 389622a6600876 |
12 | 128a3060b7742b |
13 | 58424b8183b99 |
14 | 246400b6d4911 |
15 | 102d1ddca2198 |
hex | 7782f540aca3 |
131404344110243 has 2 divisors, whose sum is σ = 131404344110244. Its totient is φ = 131404344110242.
The previous prime is 131404344110173. The next prime is 131404344110267. The reversal of 131404344110243 is 342011443404131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131404344110243 - 216 = 131404344044707 is a prime.
It is not a weakly prime, because it can be changed into another prime (131404344010243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65702172055121 + 65702172055122.
It is an arithmetic number, because the mean of its divisors is an integer number (65702172055122).
Almost surely, 2131404344110243 is an apocalyptic number.
131404344110243 is a deficient number, since it is larger than the sum of its proper divisors (1).
131404344110243 is an equidigital number, since it uses as much as digits as its factorization.
131404344110243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 131404344110243 its reverse (342011443404131), we get a palindrome (473415787514374).
The spelling of 131404344110243 in words is "one hundred thirty-one trillion, four hundred four billion, three hundred forty-four million, one hundred ten thousand, two hundred forty-three".
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