1314050911253 has 2 divisors, whose sum is σ = 1314050911254. Its totient is φ = 1314050911252.

The previous prime is 1314050911249. The next prime is 1314050911391. The reversal of 1314050911253 is 3521190504131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 901364157604 + 412686753649 = 949402^2 + 642407^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314050911253 - 2² = 1314050911249 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1314050911853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657025455626 + 657025455627.

It is an arithmetic number, because the mean of its divisors is an integer number (657025455627).

Almost surely, 2^{1314050911253} is an apocalyptic number.

It is an amenable number.

1314050911253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314050911253 is an equidigital number, since it uses as much as digits as its factorization.

1314050911253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16200, while the sum is 35.

The spelling of 1314050911253 in words is "one trillion, three hundred fourteen billion, fifty million, nine hundred eleven thousand, two hundred fifty-three".