Base | Representation |
---|---|
bin | 1011111100111000001110… |
… | …1000101100010011101111 |
3 | 1201112012221222022220200021 |
4 | 2333032003220230103233 |
5 | 3210243232420103012 |
6 | 43540400223143011 |
7 | 2524241113215301 |
oct | 277160350542357 |
9 | 51465858286607 |
10 | 13140513441007 |
11 | 42069512a0747 |
12 | 1582877444a67 |
13 | 7441b6a2a354 |
14 | 33600b907971 |
15 | 17bc354c9007 |
hex | bf383a2c4ef |
13140513441007 has 2 divisors, whose sum is σ = 13140513441008. Its totient is φ = 13140513441006.
The previous prime is 13140513440959. The next prime is 13140513441043. The reversal of 13140513441007 is 70014431504131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13140513441007 - 223 = 13140505052399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13140513441607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570256720503 + 6570256720504.
It is an arithmetic number, because the mean of its divisors is an integer number (6570256720504).
Almost surely, 213140513441007 is an apocalyptic number.
13140513441007 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140513441007 is an equidigital number, since it uses as much as digits as its factorization.
13140513441007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 34.
Adding to 13140513441007 its reverse (70014431504131), we get a palindrome (83154944945138).
The spelling of 13140513441007 in words is "thirteen trillion, one hundred forty billion, five hundred thirteen million, four hundred forty-one thousand, seven".
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