131405511014223 has 4 divisors (see below), whose sum is σ = 175207348018968. Its totient is φ = 87603674009480.

The previous prime is 131405511014213. The next prime is 131405511014243. The reversal of 131405511014223 is 322410115504131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131405511014223 - 2⁵ = 131405511014191 is a prime.

It is a super-3 number, since 3×131405511014223³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131405511014213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21900918502368 + ... + 21900918502373.

It is an arithmetic number, because the mean of its divisors is an integer number (43801837004742).

Almost surely, 2^{131405511014223} is an apocalyptic number.

131405511014223 is a deficient number, since it is larger than the sum of its proper divisors (43801837004745).

131405511014223 is an equidigital number, since it uses as much as digits as its factorization.

131405511014223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43801837004744.

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 131405511014223 its reverse (322410115504131), we get a palindrome (453815626518354).

The spelling of 131405511014223 in words is "one hundred thirty-one trillion, four hundred five billion, five hundred eleven million, fourteen thousand, two hundred twenty-three".