Base | Representation |
---|---|
bin | 10011000111110100000… |
… | …101001000011000111111 |
3 | 11122121211002202000111221 |
4 | 103013310011020120333 |
5 | 133012143330323241 |
6 | 2443400522254211 |
7 | 163636426541323 |
oct | 23076405103077 |
9 | 4577732660457 |
10 | 1314060011071 |
11 | 467320689655 |
12 | 192810057367 |
13 | 96bb8c88312 |
14 | 4785aa03983 |
15 | 242ad45e5d1 |
hex | 131f414863f |
1314060011071 has 2 divisors, whose sum is σ = 1314060011072. Its totient is φ = 1314060011070.
The previous prime is 1314060011027. The next prime is 1314060011101. The reversal of 1314060011071 is 1701100604131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1314060011071 - 219 = 1314059486783 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314060011171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657030005535 + 657030005536.
It is an arithmetic number, because the mean of its divisors is an integer number (657030005536).
Almost surely, 21314060011071 is an apocalyptic number.
1314060011071 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314060011071 is an equidigital number, since it uses as much as digits as its factorization.
1314060011071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
The spelling of 1314060011071 in words is "one trillion, three hundred fourteen billion, sixty million, eleven thousand, seventy-one".
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