131410054231 has 4 divisors (see below), whose sum is σ = 133371398392. Its totient is φ = 129448710072.

The previous prime is 131410054229. The next prime is 131410054253. The reversal of 131410054231 is 132450014131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 132450014131 = 31 ⋅4272581101.

It is a cyclic number.

It is not a de Polignac number, because 131410054231 - 2¹ = 131410054229 is a prime.

It is a super-2 number, since 2×131410054231² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131410054196 and 131410054205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131410054291) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 980671980 + ... + 980672113.

It is an arithmetic number, because the mean of its divisors is an integer number (33342849598).

Almost surely, 2^131410054231 is an apocalyptic number.

131410054231 is a deficient number, since it is larger than the sum of its proper divisors (1961344161).

131410054231 is an equidigital number, since it uses as much as digits as its factorization.

131410054231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1961344160.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 131410054231 its reverse (132450014131), we get a palindrome (263860068362).

The spelling of 131410054231 in words is "one hundred thirty-one billion, four hundred ten million, fifty-four thousand, two hundred thirty-one".