Base | Representation |
---|---|
bin | 11101111000010001011000… |
… | …111101111111011101000111 |
3 | 122020021200222120220200201021 |
4 | 131320101120331333131013 |
5 | 114211011304340042434 |
6 | 1143253021451212011 |
7 | 36452040015204106 |
oct | 3570213075773507 |
9 | 566250876820637 |
10 | 131410312034119 |
11 | 38964889313368 |
12 | 128a4247747007 |
13 | 5842c296cb9a1 |
14 | 246441615403d |
15 | 102d43cba0cb4 |
hex | 778458f7f747 |
131410312034119 has 2 divisors, whose sum is σ = 131410312034120. Its totient is φ = 131410312034118.
The previous prime is 131410312034107. The next prime is 131410312034161. The reversal of 131410312034119 is 911430213014131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131410312034119 - 211 = 131410312032071 is a prime.
It is a super-2 number, since 2×1314103120341192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131410312034819) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65705156017059 + 65705156017060.
It is an arithmetic number, because the mean of its divisors is an integer number (65705156017060).
Almost surely, 2131410312034119 is an apocalyptic number.
131410312034119 is a deficient number, since it is larger than the sum of its proper divisors (1).
131410312034119 is an equidigital number, since it uses as much as digits as its factorization.
131410312034119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 34.
The spelling of 131410312034119 in words is "one hundred thirty-one trillion, four hundred ten billion, three hundred twelve million, thirty-four thousand, one hundred nineteen".
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