Base | Representation |
---|---|
bin | 1011111100111010001010… |
… | …1010111001100001110111 |
3 | 1201112021022021001210120110 |
4 | 2333032202222321201313 |
5 | 3210300314213110033 |
6 | 43540524023034103 |
7 | 2524260034650666 |
oct | 277164252714167 |
9 | 51467267053513 |
10 | 13141034113143 |
11 | 42070991973a2 |
12 | 15829a189b933 |
13 | 74426a86c781 |
14 | 33605ab20ddd |
15 | 17bc66077363 |
hex | bf3a2ab9877 |
13141034113143 has 32 divisors (see below), whose sum is σ = 18203072025600. Its totient is φ = 8425382904576.
The previous prime is 13141034113117. The next prime is 13141034113219. The reversal of 13141034113143 is 34131143014131.
It is not a de Polignac number, because 13141034113143 - 213 = 13141034104951 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13141034113143.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13141034113243) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 30201430 + ... + 30633452.
It is an arithmetic number, because the mean of its divisors is an integer number (568846000800).
Almost surely, 213141034113143 is an apocalyptic number.
13141034113143 is a deficient number, since it is larger than the sum of its proper divisors (5062037912457).
13141034113143 is a wasteful number, since it uses less digits than its factorization.
13141034113143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 435231.
The product of its (nonzero) digits is 5184, while the sum is 30.
Adding to 13141034113143 its reverse (34131143014131), we get a palindrome (47272177127274).
The spelling of 13141034113143 in words is "thirteen trillion, one hundred forty-one billion, thirty-four million, one hundred thirteen thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •