Base | Representation |
---|---|
bin | 1011111100111010001010… |
… | …1111011100111000110111 |
3 | 1201112021022100022102121202 |
4 | 2333032202233130320313 |
5 | 3210300320014302201 |
6 | 43540524104403115 |
7 | 2524260051051215 |
oct | 277164257347067 |
9 | 51467270272552 |
10 | 13141035306551 |
11 | 4207099931a89 |
12 | 15829a217649b |
13 | 74426ab99a29 |
14 | 33605ad51cb5 |
15 | 17bc66210c6b |
hex | bf3a2bdce37 |
13141035306551 has 4 divisors (see below), whose sum is σ = 13141070557704. Its totient is φ = 13141000055400.
The previous prime is 13141035306547. The next prime is 13141035306559. The reversal of 13141035306551 is 15560353014131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13141035306551 - 22 = 13141035306547 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13141035306559) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17060360 + ... + 17813981.
It is an arithmetic number, because the mean of its divisors is an integer number (3285267639426).
Almost surely, 213141035306551 is an apocalyptic number.
13141035306551 is a deficient number, since it is larger than the sum of its proper divisors (35251153).
13141035306551 is an equidigital number, since it uses as much as digits as its factorization.
13141035306551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35251152.
The product of its (nonzero) digits is 81000, while the sum is 38.
The spelling of 13141035306551 in words is "thirteen trillion, one hundred forty-one billion, thirty-five million, three hundred six thousand, five hundred fifty-one".
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