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131410444411 is a prime number
BaseRepresentation
bin111101001100010101…
…1000100000001111011
3110120012012221020121201
41322120223010001323
54123112033210121
6140211421515031
712331321230121
oct1723053040173
9416165836551
10131410444411
1150804851974
1221575112a77
13c51316c21c
146508939911
153641abce91
hex1e98ac407b

131410444411 has 2 divisors, whose sum is σ = 131410444412. Its totient is φ = 131410444410.

The previous prime is 131410444393. The next prime is 131410444423. The reversal of 131410444411 is 114444014131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131410444411 - 25 = 131410444379 is a prime.

It is a super-2 number, since 2×1314104444112 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131410444411.

It is not a weakly prime, because it can be changed into another prime (131410444111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65705222205 + 65705222206.

It is an arithmetic number, because the mean of its divisors is an integer number (65705222206).

Almost surely, 2131410444411 is an apocalyptic number.

131410444411 is a deficient number, since it is larger than the sum of its proper divisors (1).

131410444411 is an equidigital number, since it uses as much as digits as its factorization.

131410444411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3072, while the sum is 28.

Adding to 131410444411 its reverse (114444014131), we get a palindrome (245854458542).

The spelling of 131410444411 in words is "one hundred thirty-one billion, four hundred ten million, four hundred forty-four thousand, four hundred eleven".