Base | Representation |
---|---|
bin | 10011000111110111000… |
… | …111101101101111110111 |
3 | 11122121221122201112122101 |
4 | 103013313013231233313 |
5 | 133012244410120043 |
6 | 2443405543442531 |
7 | 163640616240424 |
oct | 23076707555767 |
9 | 4577848645571 |
10 | 1314111020023 |
11 | 46734745940a |
12 | 192825156447 |
13 | 96bc6707a29 |
14 | 478636c0d4b |
15 | 242b2b8824d |
hex | 131f71edbf7 |
1314111020023 has 4 divisors (see below), whose sum is σ = 1314784579648. Its totient is φ = 1313437460400.
The previous prime is 1314111019999. The next prime is 1314111020069. The reversal of 1314111020023 is 3200201114131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1314111020023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1314111320023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 336776886 + ... + 336780787.
It is an arithmetic number, because the mean of its divisors is an integer number (328696144912).
Almost surely, 21314111020023 is an apocalyptic number.
1314111020023 is a deficient number, since it is larger than the sum of its proper divisors (673559625).
1314111020023 is an equidigital number, since it uses as much as digits as its factorization.
1314111020023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 673559624.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1314111020023 its reverse (3200201114131), we get a palindrome (4514312134154).
The spelling of 1314111020023 in words is "one trillion, three hundred fourteen billion, one hundred eleven million, twenty thousand, twenty-three".
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