Base | Representation |
---|---|
bin | 1011111100111010011101… |
… | …1101001011100111100111 |
3 | 1201112021111212010221222002 |
4 | 2333032213131023213213 |
5 | 3210301000241401203 |
6 | 43540540011555515 |
7 | 2524262031263045 |
oct | 277164735134747 |
9 | 51467455127862 |
10 | 13141114403303 |
11 | 420712a5465a7 |
12 | 1582a0475bb9b |
13 | 7442813a1c43 |
14 | 336067661395 |
15 | 17bc6d136d88 |
hex | bf3a774b9e7 |
13141114403303 has 2 divisors, whose sum is σ = 13141114403304. Its totient is φ = 13141114403302.
The previous prime is 13141114403257. The next prime is 13141114403323. The reversal of 13141114403303 is 30330441114131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13141114403303 - 26 = 13141114403239 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13141114403323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570557201651 + 6570557201652.
It is an arithmetic number, because the mean of its divisors is an integer number (6570557201652).
Almost surely, 213141114403303 is an apocalyptic number.
13141114403303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141114403303 is an equidigital number, since it uses as much as digits as its factorization.
13141114403303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 13141114403303 its reverse (30330441114131), we get a palindrome (43471555517434).
The spelling of 13141114403303 in words is "thirteen trillion, one hundred forty-one billion, one hundred fourteen million, four hundred three thousand, three hundred three".
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