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131411352420553 is a prime number
BaseRepresentation
bin11101111000010010010110…
…111110110000000011001001
3122020021210200002120210121011
4131320102112332300003021
5114211020422204424203
61143253313014243521
736452104550302522
oct3570222676600311
9566253602523534
10131411352420553
1138965272611067
12128a44980565a1
13584306410956a
1424644b43b5849
15102d49e1ad76d
hex778496fb00c9

131411352420553 has 2 divisors, whose sum is σ = 131411352420554. Its totient is φ = 131411352420552.

The previous prime is 131411352420497. The next prime is 131411352420559. The reversal of 131411352420553 is 355024253114131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120325169534089 + 11086182886464 = 10969283^2 + 3329592^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131411352420553 is a prime.

It is not a weakly prime, because it can be changed into another prime (131411352420559) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65705676210276 + 65705676210277.

It is an arithmetic number, because the mean of its divisors is an integer number (65705676210277).

Almost surely, 2131411352420553 is an apocalyptic number.

It is an amenable number.

131411352420553 is a deficient number, since it is larger than the sum of its proper divisors (1).

131411352420553 is an equidigital number, since it uses as much as digits as its factorization.

131411352420553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 40.

The spelling of 131411352420553 in words is "one hundred thirty-one trillion, four hundred eleven billion, three hundred fifty-two million, four hundred twenty thousand, five hundred fifty-three".