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131411551633 is a prime number
BaseRepresentation
bin111101001100010111…
…1010010010110010001
3110120012022000111102221
41322120233102112101
54123112324123013
6140211501341041
712331333521145
oct1723057222621
9416168014387
10131411551633
115080543882a
1221575567781
13c51346919b
146508b47225
153641c3b08d
hex1e98bd2591

131411551633 has 2 divisors, whose sum is σ = 131411551634. Its totient is φ = 131411551632.

The previous prime is 131411551613. The next prime is 131411551651. The reversal of 131411551633 is 336155114131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90016800784 + 41394750849 = 300028^2 + 203457^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131411551633 is a prime.

It is not a weakly prime, because it can be changed into another prime (131411551613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65705775816 + 65705775817.

It is an arithmetic number, because the mean of its divisors is an integer number (65705775817).

Almost surely, 2131411551633 is an apocalyptic number.

It is an amenable number.

131411551633 is a deficient number, since it is larger than the sum of its proper divisors (1).

131411551633 is an equidigital number, since it uses as much as digits as its factorization.

131411551633 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 16200, while the sum is 34.

Adding to 131411551633 its reverse (336155114131), we get a palindrome (467566665764).

The spelling of 131411551633 in words is "one hundred thirty-one billion, four hundred eleven million, five hundred fifty-one thousand, six hundred thirty-three".