Base | Representation |
---|---|
bin | 111101001100010111… |
… | …1010010010110100011 |
3 | 110120012022000111110121 |
4 | 1322120233102112203 |
5 | 4123112324123101 |
6 | 140211501341111 |
7 | 12331333521202 |
oct | 1723057222643 |
9 | 416168014417 |
10 | 131411551651 |
11 | 50805438846 |
12 | 21575567797 |
13 | c5134691b3 |
14 | 6508b47239 |
15 | 3641c3b0a1 |
hex | 1e98bd25a3 |
131411551651 has 2 divisors, whose sum is σ = 131411551652. Its totient is φ = 131411551650.
The previous prime is 131411551633. The next prime is 131411551729. The reversal of 131411551651 is 156155114131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131411551651 - 215 = 131411518883 is a prime.
It is not a weakly prime, because it can be changed into another prime (131411531651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65705775825 + 65705775826.
It is an arithmetic number, because the mean of its divisors is an integer number (65705775826).
Almost surely, 2131411551651 is an apocalyptic number.
131411551651 is a deficient number, since it is larger than the sum of its proper divisors (1).
131411551651 is an equidigital number, since it uses as much as digits as its factorization.
131411551651 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9000, while the sum is 34.
Adding to 131411551651 its reverse (156155114131), we get a palindrome (287566665782).
The spelling of 131411551651 in words is "one hundred thirty-one billion, four hundred eleven million, five hundred fifty-one thousand, six hundred fifty-one".
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