Base | Representation |
---|---|
bin | 1011111100111010111001… |
… | …1000001000101111101011 |
3 | 1201112021210221122100221111 |
4 | 2333032232120020233223 |
5 | 3210301220003140243 |
6 | 43540555320451151 |
7 | 2524264641255412 |
oct | 277165630105753 |
9 | 51467727570844 |
10 | 13141230521323 |
11 | 420718a046803 |
12 | 1582a37619ab7 |
13 | 74429c469c28 |
14 | 336078c4a479 |
15 | 17bc7842239d |
hex | bf3ae608beb |
13141230521323 has 2 divisors, whose sum is σ = 13141230521324. Its totient is φ = 13141230521322.
The previous prime is 13141230521317. The next prime is 13141230521399. The reversal of 13141230521323 is 32312503214131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13141230521323 - 29 = 13141230520811 is a prime.
It is a super-3 number, since 3×131412305213233 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (13141230522323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570615260661 + 6570615260662.
It is an arithmetic number, because the mean of its divisors is an integer number (6570615260662).
Almost surely, 213141230521323 is an apocalyptic number.
13141230521323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141230521323 is an equidigital number, since it uses as much as digits as its factorization.
13141230521323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 13141230521323 its reverse (32312503214131), we get a palindrome (45453733735454).
The spelling of 13141230521323 in words is "thirteen trillion, one hundred forty-one billion, two hundred thirty million, five hundred twenty-one thousand, three hundred twenty-three".
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