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13141230521317 is a prime number
BaseRepresentation
bin1011111100111010111001…
…1000001000101111100101
31201112021210221122100221021
42333032232120020233211
53210301220003140232
643540555320451141
72524264641255403
oct277165630105745
951467727570837
1013141230521317
11420718a0467a8
121582a37619ab1
1374429c469c22
14336078c4a473
1517bc78422397
hexbf3ae608be5

13141230521317 has 2 divisors, whose sum is σ = 13141230521318. Its totient is φ = 13141230521316.

The previous prime is 13141230521269. The next prime is 13141230521323. The reversal of 13141230521317 is 71312503214131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10197350102241 + 2943880419076 = 3193329^2 + 1715774^2 .

It is a cyclic number.

It is not a de Polignac number, because 13141230521317 - 239 = 12591474707429 is a prime.

It is a super-2 number, since 2×131412305213172 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13141230521417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570615260658 + 6570615260659.

It is an arithmetic number, because the mean of its divisors is an integer number (6570615260659).

Almost surely, 213141230521317 is an apocalyptic number.

It is an amenable number.

13141230521317 is a deficient number, since it is larger than the sum of its proper divisors (1).

13141230521317 is an equidigital number, since it uses as much as digits as its factorization.

13141230521317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 34.

Adding to 13141230521317 its reverse (71312503214131), we get a palindrome (84453733735448).

The spelling of 13141230521317 in words is "thirteen trillion, one hundred forty-one billion, two hundred thirty million, five hundred twenty-one thousand, three hundred seventeen".