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131412310031543 is a prime number
BaseRepresentation
bin11101111000010011010000…
…000011101111110010110111
3122020021220010211111110220212
4131320103100003233302313
5114211024402332002133
61143253552023220035
736452140355665352
oct3570232003576267
9566256124443825
10131412310031543
1138965714112402
12128a47048a761b
135843187624698
14246456564b299
15102d5082ba148
hex7784d00efcb7

131412310031543 has 2 divisors, whose sum is σ = 131412310031544. Its totient is φ = 131412310031542.

The previous prime is 131412310031441. The next prime is 131412310031567. The reversal of 131412310031543 is 345130013214131.

It is a strong prime.

It is an emirp because it is prime and its reverse (345130013214131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131412310031543 - 212 = 131412310027447 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131412310331543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706155015771 + 65706155015772.

It is an arithmetic number, because the mean of its divisors is an integer number (65706155015772).

Almost surely, 2131412310031543 is an apocalyptic number.

131412310031543 is a deficient number, since it is larger than the sum of its proper divisors (1).

131412310031543 is an equidigital number, since it uses as much as digits as its factorization.

131412310031543 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 131412310031543 its reverse (345130013214131), we get a palindrome (476542323245674).

The spelling of 131412310031543 in words is "one hundred thirty-one trillion, four hundred twelve billion, three hundred ten million, thirty-one thousand, five hundred forty-three".