Base | Representation |
---|---|
bin | 11101111000010011010000… |
… | …000011101111110010110111 |
3 | 122020021220010211111110220212 |
4 | 131320103100003233302313 |
5 | 114211024402332002133 |
6 | 1143253552023220035 |
7 | 36452140355665352 |
oct | 3570232003576267 |
9 | 566256124443825 |
10 | 131412310031543 |
11 | 38965714112402 |
12 | 128a47048a761b |
13 | 5843187624698 |
14 | 246456564b299 |
15 | 102d5082ba148 |
hex | 7784d00efcb7 |
131412310031543 has 2 divisors, whose sum is σ = 131412310031544. Its totient is φ = 131412310031542.
The previous prime is 131412310031441. The next prime is 131412310031567. The reversal of 131412310031543 is 345130013214131.
It is a strong prime.
It is an emirp because it is prime and its reverse (345130013214131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131412310031543 - 212 = 131412310027447 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131412310331543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706155015771 + 65706155015772.
It is an arithmetic number, because the mean of its divisors is an integer number (65706155015772).
Almost surely, 2131412310031543 is an apocalyptic number.
131412310031543 is a deficient number, since it is larger than the sum of its proper divisors (1).
131412310031543 is an equidigital number, since it uses as much as digits as its factorization.
131412310031543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 32.
Adding to 131412310031543 its reverse (345130013214131), we get a palindrome (476542323245674).
The spelling of 131412310031543 in words is "one hundred thirty-one trillion, four hundred twelve billion, three hundred ten million, thirty-one thousand, five hundred forty-three".
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